
Do you know how much your credit accounts cost you each month? Can you achieve your financial goals even if you don't work on Wall Street?
Have you ever wanted to compare savings or investment plans offering different rates of return? Have you wondered how long it would take you to save for the down payment on a house or to buy a car for cash?
Have you longed to be able to compare the cost of loans with different rates, different amounts, and different time periods? Or, have you wished that you could compare the monthly payments for different loan proposals?
Do you know how long it will take you to accumulate enough money to send the children to college? Have you wondered about the amount of money you would have available to finance your retirement if you saved $2,000 a year? Or, would you like to know how long your savings will last if you withdraw $1,000 per month? Have you wondered what impact inflation will have on your retirement “nest egg?”
Such problems can be solved quickly and easily using a financial calculator.* Although calculations involving compound interest, periodic payments, and declining or increasing balances are complex, a financial calculator* makes them simple. Regardless of your mathematical skills and training, you can make such calculations quickly and easily. This publication shows you how.
*A number of good financial calculators are on the market. This publication uses Texas Instruments (TI) calculator BA II Plus and HP 10B II.
Topics covered include:
The Financial Calculator
The Magic of Compounding
Inflation
Future Value of a Present Sum
Present Value of a Future Sum
Computing Retirement Payments
Withdrawals from Investments –
Time money will last
Amount of money to withdraw
How Much Money do You Need?
The math function (operation) keys are located on the right of your Texas Instrument calculator and across the top of the HP 10B II. Press the keys in order of math function desired. Think through the process and then press the appropriate keys.
Practice each math function until you feel comfortable with the pressure that must be applied to the keys to have the number appear on the display screen.
The Financial Keys for the Hewlett Packard 10B II and/or Texas Instrument BA II Plus. |
|
Value Keys |
Command Keys |
[N][%][PMT][PV][FV] |
[2nd][CPT][+/-] |
Key |
Function of Key |
[N] |
=Number of periods [often 1 year but could be 1 day, week or month] |
[1/y] or [1/yr] |
= Interest per period |
[PV] |
= Present Value |
[FV] |
= Future Value |
[+/-] |
= This key is used to change the sign of the number in the window |
[2nd] |
= On the TI BAII Plus this key changes the function of keys from the function written in white on the key to the function written in orange above the key. |
[CPT] |
= On the TI BAII Plus this key is pressed to ask the calculator to solve for {compute} whichever “value” key is pressed next and for end of the month payments. (Press the [CPT] key and then the “value” key for the unknown value). |
All five value keys may not be needed for a given problem. If you know three values, you can solve for a fourth. If you know four you can solve for the fifth. For most problems the order in which the problem is entered into the calculator will not make any difference. The only requirement is that the known values be entered before you press the [CPT] key to solve for the unknown value.
The value of money changes over time. A dollar received today is worth more than a dollar received a year from now. This is the opportunity cost of postponing the use of that dollar for one year. Compounding interest is important because it forms the basis of many financial calculations. Perhaps you are familiar with the terms “compounded annually, quarterly, or daily.” These expressions mean that interest is figured on principal as frequently as the period mentioned. This interest is then added to the previous principal before the next calculation is made. Annual compounding means that this calculation is made once each year. The new interest is added to the principal before performing the next years calculation.
Directions: Use your Financial Calculator Texas Instruments BAII Plus or Hewlett Packard 10B II to compute the following financial problems. Check answer section to see if your answers are correct.
The first example under each section provides the procedure used to solve that type of financial problem. But before we start; set your calculator. Clear memory, set decimal places, and set compounding periods to annual unless instructed otherwise. [Clear memory after each problem]
Set Calculator |
HP 10B II |
TI BAII Plus |
Clear memory |
[•] [Clear All] |
[2nd][MEM] |
[Enter][2nd][Quit] |
||
[2nd][CLR work] [2nd][quit] |
||
[2nd][CLR TVM] |
||
Set decimal place 4 is used in this example |
[•][DISP]4 |
[2nd][Format]4[Enter][2nd][quit] |
Set floating decimal point |
[•][DISP] |
[2nd][Format]9[Enter][2nd][quit] |
Set compounding periods annually |
[•]1[P/YR] |
2nd][P/Y]1[Enter] [2nd][quit] |
Monthly |
[•][P/YR]
|
[2nd][P/Y]12[enter] [2nd][quit] |
*[•] is orange button
1. Over the past 100 years stock prices have appreciated on average 7% per year. If your great grandfather had left you $1,000 in stock a hundred years ago, what would be the value of your account today?
HP 10B II |
TI BAII Plus |
|
Present Value |
1,000 [+/-][PV] |
1000 [+/-][PV] |
Time Period |
100 [N] |
100 [N] |
Interest Rate |
7 [I/YR] |
7 [I/Y] |
Results |
[FV] 867,716 |
[CPT][FV] 867,716 |
2. Paul inherited $20,000 from his mother. He is using this to begin his retirement fund. If he invests his inheritance at 6% annually, what will be the value in 27 years when he is ready to retire?
3. Betty, 40, has $15,000 in her IRA. If the annual interest rate averages 4%, how much will she have by age 62?
4. She plans to use this for her retirement. Sarah is currently 45. If she receives 6% annually on the bonds, how much will she have by age 60?
5. Ryan has $38,000 in a Roth IRA. He plans to retire in 12 years. How much will his IRA be worth if he receives 4% annual interest?
6. JoAnn currently lives on $1,500 per month. This is adequate for her today. If the annual inflation rate is 4.2% how much money will JoAnn need in 15 years to maintain her current life style?
HP 10B II |
TI BAII Plus |
|
Present Value |
1500[+/-] [PV] |
1500[+/-][PV] |
| Time | 15[N] | 15[N] |
Inflation Rate |
4.2[I/YR] | 4.2[I/Y] |
| Results | [FV]2,780 | [CPT][FV]2,780 |
7. James thinks that he can live on $1,200 per month if he retired today. If the inflation rate is 5%, how much will James need in 25 years to maintain today's purchasing power of $1,200 per month?
8. A monthly retirement goal for Jim is $2,000. If the inflation rate averages 3% per year, how much will Jim need to equal the buying power of $2,000 in 20 years?
9. Cathy, 35, is saving $3,000 each year in an IRA with an interest rate of 5% annually. What will the balance of the account be when she retires in 30 years.
HP 10B II |
TI BAII Plus |
|
Payment |
3,000[+/-][PMT] |
3,000[+/-][PMT] |
Time Period |
30[N] |
30[N] |
Interest Rate |
5[I/YR] |
5[I/Y] |
Future Value |
[FV]199,317 |
[CPT][FV]199,317 |
10. Ann plans to save $1,000 per year and put it in her IRA earning 4% annually. Ann is now 25. If she follows her plan how much money will she have at age 65?
11. Fred is five years away from retirement. He has started saving $3,000 each year. If he earns 4% annually, how much money will he have accumulated when he retires?
12. George and Margean are planning to retire in 15 years. Their children are on their own and their house is paid for. Their assets include: $15,000 in certificates of deposit, $12,000 cash value in life insurance, and $23,000 in IRAs. Their plan is to deposit $5,000 annually in their retirement funds. These accounts are averaging an annual interest rate of 5%. What will be the value of these assets in 15 years?
HP 10B II |
TI BAII Plus |
|
Present value |
50,000[+/-][PV] |
15,000[+]12,000[+] 23,000[+] |
50,000[+/-][PV] |
[+/-][PV] |
|
Payment |
5,000[+/-][PMT] |
5,000[+/-][PMT] |
Time period |
15[N] |
15[N] |
Interest rate |
5[I/YR] |
5[I/Y] |
Future value |
[FV]211,839 |
[CPT][FV]211,839 |
13. The balance of Nancy's tax-deferred annuity is $30,000. If she adds $4,000 per year for 15 years what will be the value of her account at a 4% interest rate.
14. Betsy, age 35, has $15,000 in her ROTH IRA. If she adds $2,000 per year for 25 years, how much will she have if the account earns 5% annually?
15. What would Betsy have if she deposited $3,000 per year instead of $2,000?
16. Ralph is 20 years from retirement. He plans to make monthly payments of $350 to fund his retirement. If he can get an interest rate of 6%, what will be the value of his account when he retires?
HP 10B II |
BAII Plus |
|
Payment |
350[+/-][PMT] |
350[+/-][PMT] |
Time Period |
20[X] 12[=]240[N] |
20[X]12[=]240[N] |
Interest Rate |
6[/]12[=].5[I/YR] |
6[/]12[=].5[I/Y] |
Future Value |
[FV]161,714 |
[CPT][FV]161,714 |
17. If Bill age 42, has savings that earn an annual interest rate of 6%, how much will he have by age 60, if he saves $400 each month?
18. Fred saves $325 monthly; he earns 4% annually. How much will he have in 5 years?
19. Ben has $65,000 in his retirement fund. He will retire in 8 years. If he saves $660 per month and adds it to his lump sum, how much will he have if he earns 5.4% annually?
HP 10B II |
TI BAII Plus |
|
Present Value |
65,000[+/-][PV] |
65,000[+/-][PV] |
Payment |
660[+/-][PMT] |
660[+/-][PMT] |
Time Period |
8X12=[N] |
8X12=[N] |
Interest Rate |
5.4/12=[I/YR] |
5.4/12=[I/Y] |
Future Value |
[FV]179,055 |
[CPT][FV]179,055 |
20. James and Pam have paid for their house. They plan to add the $750 monthly they paid on the house to their $35,000 retirement account. If they can get 6% on all these funds, how much money will they have in 5 years?
21. Joan, 40, has saved $30,000 in an IRA. She plans to retire at age 65. She currently adds $200 per month to the account. How much will she have when she retires if she averages a 6% rate of return?
22. Delbert, age 65, has investment assets, in a deferred compensation plan, of $100,000. If he starts taking $950 per month from the fund to supplement his Social Security payments, how long will his fund last? Assume he has an annual interest rate of 6.25%. [Reminder clear calculator.]
HP 10B II |
TI BAII Plus |
|
Present value |
100,000[PV] |
100,000[PV] |
Payments |
950[+/-][PMT] |
950[+/-][PMT] |
Interest rate |
6.25/12=[I/YR] |
6.25/12=[I/Y] |
Payments will last |
[N]152.96 Months[/]12=1 2.75Years |
[CPT][N]152.96 Months[/]12 =12.75 years |
23. Patricia, 62, has $53,000 invested. If she makes monthly withdrawals of $800, how long will the fund last if she averages 6.2% rate of interest?
24. Tim has a retirement fund of $103,000. If he withdraws $1200 per month, how long will the fund last assuming an annual interest rate of 4%?
25. Cheryl=s retirement fund has a current balance of $65,000. She needs $550 per month from this fund to supplement her Social Security. If she gets 5.5% how long will the fund last?
26. Sam age 70 has an IRA balance of $45,000. If he decides to take $995 monthly, how long will the fund last, assuming a 4% annual growth rate?
27. David wants to use his $96,000 IRA to supplement his pension. How much can he take out monthly if he wants the money to last 20 years and he is getting 6% annual return?
HP 10B II |
TI BAII Plus |
|
Present value |
96,000[+/-][PV] |
96,000[+/-][PV] |
Interest rate |
6[/]12[=][I/YR] |
6[/]12[=][I/YR] |
Time |
20[X]12=[N] |
20[X]12=[N] |
Payment amount |
[PMT] 688 |
[CPT][PMT] =688 |
28. Bob has $90,000 in his retirement fund. He averages 4% annual interest rate. His life expectancy is 12.1 years. How much money can he withdraw per month if his money is to last
29. Ruth has $150,000 in a tax-deferred account. She wants it to last 25 years. Assume an annual interest rate of 6%. (a) How much can she withdraw monthly? (b) If she decides to withdraw $2,000 monthly, how long will the fund last? (Hint: $2,000 is the payment)
30. Joe would like to withdraw $1,250 per month for 20 years from his retirement fund. If he gets 4% annual rate of return on his money how much money will he need?
HP 10B II |
TI BAII Plus |
|
Time |
20[X] 12=[N] |
20[X]12 = [N] |
Interest |
4[/]12=[I/YR] |
4[/]12=[I/Y] |
Payment |
1250[+/-][PMT] |
1250[+/-][PMT] |
[PV] 206,277 |
[CPT][PV]206,277 |
31. How much will Brenda need in her retirement fund if she plans to withdraw $600 per month for 15 years if the account earns 5% annually?
32. How much money will Taylor need if she plans to withdraw $800 per month for 25 years? Assume that she will get an average annual return of 4.5%.
33. Jimmy would like to have his retirement fund provide a monthly income of $1,800 for his life expectancy of 15 years. How much does he need in his retirement fund if the interest rate is only 3.6%?
Note: the following pages contain answers to problems in this publication.
| 2 | HP 10B II |
TI TI BAII Plus |
Present Value |
20,000[+/-][PV] |
2,000[+/-][PV] |
Time Period |
27[N] |
27[N] |
Interest Rate |
6 [I/YR] |
6 [I/Y] |
Results |
[FV] 96,447 |
[CPT][FV] 96,447 |
| 3 | ||
| Present Value | 15,000[+/-][PV] |
15,000[+/-][PV] |
| Time Period | 62[-]40[=]22[N] |
62[-]40[=]22[N] |
| Interest Rate | 4 [I/YR] |
4 [I/Y] |
| Results | [FV] 35,549 |
[CPT][FV] 35,549 |
| 4 | ||
| Present Value | 50,000[+/-][PV] |
50,000[+/-][PV] |
| Time Period | 60[-]45[=]15[N] |
62[-]40[=]22[N] |
| Interest Rate | 6 [I/YR] |
6 [I/Y] |
| Results | [FV] 119,828 |
[CPT][FV] 119,828 |
| 5 | ||
| Present Value | 38,000[+/-][PV] |
38,000[+/-][PV] |
| Time Period | 12[N] |
12[N] |
| Interest Rate | 4 [I/YR] |
4 [I/Y] |
| Results | [FV] 60,839 |
[CPT][FV] 60,839 |
| 7 | ||
| Present Value | 1,200[+/-][PV] |
1,200[+/-][PV] |
| Time Period | 25[N] |
25[N] |
| Interest Rate | 5 [I/YR] |
5 [I/Y] |
| Results | [CPT][FV] 4,064 |
|
| 8 | ||
| Present Value | 2,000[+/-][PV] |
2,000[+/-][PV] |
| Time Period | 20[N] |
20[N] |
| Interest Rate | 3 [I/YR] |
3 [I/Y] |
| Results | [FV] 3,612 |
[CPT][FV] 3,612 |
| 10 | ||
| Payment | 1,000[+/-][PMT] |
1,000[+/-][PMT] |
| Time Period | 40[N] |
40[N] |
| Interest Rate | 4 [I/YR] |
4 [I/Y] |
| Results | [FV] 95,026 |
[CPT][FV] 95,026 |
| 11 | ||
| Payment | 3,000[+/-][PMT] |
3,000[+/-][PMT] |
| Time Period | 5[N] |
5[N] |
| Interest Rate | 4 [I/YR] |
4 [I/Y] |
| Results | [FV] 16,249 |
[CPT][FV] 16,249 |
| 13 | ||
| Present Value | 30,000[+/-][PV] |
30,000[+/-][PV] |
| Payment | 4,000[+/-][PMT] | 4,000[+/-][PMT] |
| Time Period | 15[N] |
15[N] |
| Interest Rate | 4 [I/YR] |
4 [I/Y] |
| Future Value | [FV] 134,123 |
[CPT][FV] 134,123 |
| 15 | ||
Present Value |
15,000[+/-][PV] |
15,000[+/-][PV] |
| Payment | 2,000[+/-][PMT] | 2,000[+/-][PMT] |
Time Period |
25[N] |
25[N] |
Interest Rate |
5 [I/YR] |
5 [I/Y] |
Future Value |
[FV] 146,250 |
[CPT][FV] 146,250 |
| 15 | ||
| Present Value | 15,000[+/-][PV] |
15,000[+/-][PV] |
| Payment | 3,000[+/-][PMT] | 3,000[+/-][PMT] |
| Time Period | 25[N] |
25[N] |
| Interest Rate | 5 [I/YR] |
5 [I/Y] |
| Future Value | [FV] 193,977 |
[CPT][FV] 193,977 |
| 17 | ||
| Payment | 400[+/-][PMT] |
400[+/-][PMT] |
| Time Period | 60-42=18X12[N] |
60-42=18X12=[N] |
| Interest Rate | 6 / 2 = [1/YR] |
6 / 2 = [I/Y] |
| Future Value | [FV] 154,941 |
[CPT][FV] 154,941 |
| 18 | ||
| Payment | 325[+/-][PMT] |
325[+/-][PMT] |
| Time Period | 5X12=[N] |
5X12=[N] |
| Interest Rate | 4/2=[1/YR] |
4/2=[I/Y] |
| Future Value | [FV] 21,547 |
[CPT][FV] 21,547 |
| 20 | ||
| Present Value | 35,000[+/-][PV] |
35,000[+/-][PV] |
| Payment | 750[+/-][PMT] |
750[+/-][PMT] |
| Time Period | 5X12=[N] |
5X12=[N] |
| Interest Rate | 6/12=[1/YR] |
6/12=[1/Y] |
| Future Value | [FV] 99,537 |
[CPT][FV] 99,537 |
| 21 | ||
| Present Value | 30,000[+/-][PV] |
53,000[PV] |
| Payment | 200[+/-][PMT] |
200[+/-][PMT] |
| Time Period | 65-40[=]X12=N | 65-40[=]X12=[N] |
| Interest Rate | 6/12=[1/YR] |
6/12=[1/Y] |
| Future Value | [FV] 272,548 |
[CPT][FV] 272,548 |
| 23 | ||
| Present Value | 53,000[PV] |
53,000[PV] |
| Payment | 800[+/-][PMT] |
800[+/-][PMT] |
| Interest Rate | 6.2/12=[1/YR] |
6.2/12=[1/Y] |
| Time Period | [N]81.3/12= [6.78]years] |
[CPT][N]= 81.3 mos.= 6.78 years |
| 24 | ||
| Present Value | 103,000[PV] |
103,000[PV] |
| Payment | 1,200[+/-][PMT] |
1,200[+/-][PMT] |
| Interest Rate | 4/12=[1/YR] |
4/12=[1/Y] |
| Time Period | [N] 8.4years [101.28 months] |
[CPT][N]= 101.28 mos.or 8.44 years |
| 25 | ||
| Present Value | 65,000[PV] |
65,000[PV] |
| Payment | 550[+/-][PMT] |
550[+/-][PMT] |
| Interest Rate | 5.5/12=[1/YR] |
5.5/12=[1/Y] |
| Time Period | [N] 170.61 months 14.22 years |
[CPT][N]= 170.61 mos.or 14.22 years |
| 26 | ||
| Present Value | 45,000[PV] |
45,000[PV] |
| Payment | 995[+/-][PMT] |
995[+/-][PMT] |
| Interest Rate | 4/12=[1/YR] |
4/12=[1/Y] |
| Time Period | [N] 49.1 mos. 4.09 years |
[CPT][N]= 49.1 mos. or 4.09 years |
| 28 | ||
| Present Value | 90,000[+/-][PV] |
90,000[+/-][PV] |
| Interest Rate | 4/12=[1/YR] |
4/12=[1/Y] |
| Years | 12.1X12=[N] |
12.1X12=[N] |
| [PMT] | 783 |
[CPT][PMT] 783 |
| 29a | ||
| Present Value | 150,000[+/-][PV] |
150,000[+/-][PV] |
| Time | 25 X 12 = [N] |
25 X 12 = [N] |
| Interest | 6/12 =[1/YR] |
6/12 = [1/Y] |
| [PMT] | 966.45 |
[CPT][PMT]=966.45 |
| 29b | ||
| Present Value | 150,000[+/-][PV] |
150,000[+/-][PV] |
| Interest Rate | 6/12=[1/YR] |
6/12=[1/Y] |
| Payment | 2000 [PMT] |
2000 [PMT] |
| Time Period | [N] 94.2 months or 7.85 years |
[CPT][N] 94.2 mos. or 7.85 years |
| 31 | ||
| Time | 15 X 12 = [N] | 15 X 12 = [N] |
| Interest | 5/12=[1/YR] | 5/12=[1/Y] |
| Payment | 600 [+/-][PMT] [PV] 75873 |
600 [+/-][PMT] [PV] 75873 |
| 32 | ||
| Time | 25 X 12 = [N] | 25 X 12 = [N] |
| Interest | 5/12=[1/YR] | 5/12=[1/Y] |
| Payment | 600 [+/-][PMT] [PV] 75873 |
600 [+/-][PMT] [PV] 75873 |
This document is FCS5263/FY442, one of a series of the Department of Family, Youth and Community Sciences, Florida Cooperative Extension Service, University of Florida, UF/IFAS, Gainesville, FL 32611. First published: July 2003. Reviewed July 2006. Reviewed by Mary N. Harrison, professor, Department of Family, Youth and Community Sciences; and Patricia Tengel, Ph.D., CFP, Maryland. Please visit the EDIS Web site at http://edis.ifas.ufl.edu
Josephine Turner, Ph.D., CFP, professor, Family, Youth and Consumer Economics, Department of Family, Youth and Community Sciences, Cooperative Extension Service, UF/IFAS, Gainesville, FL 32611.
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For more information on obtaining other extension publications,
contact your county Cooperative Extension service.
U.S. Department of Agriculture, Cooperative Extension Service,
University of Florida, IFAS, Florida A. & M. University Cooperative
Extension Program, and Boards of County Commissioners Cooperating. Millie Ferrer-Chancy,
Interim Dean.